SOLUTION: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and Train B is traveling at 110 miles per hour. Train A passes a s

Algebra ->  Systems-of-equations -> SOLUTION: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and Train B is traveling at 110 miles per hour. Train A passes a s      Log On


   

Question 266368: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and Train B is traveling at 110 miles per hour. Train A passes a station at 10:15 A.M. If train B passes the same station at 10:27 A.M., at what time will train B catch up to train A?
I know the equation is
100t = 110(t - something)
I know there is 12 minutes difference, but I do not know how to put 12 minutes in a decimal form.
Could someone please help me with this, I would appreciate it very much.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
100t=110(t-12/60)
100t=110(t-1/5)
100t=110t-22
100t-110t=-22
-10t=-22
t=-22/-10
t=2.2 hours after train A leaves the station they will meet.
OR: 10:15+2:12=12.27 is the time of the meet.
Proof:
100*2.2=110(2.2-1/5)
220=242-22
220=220