Question 266193: A fair die is rolled 6 times. What is the probability of having no 1 and no 2 among the rolls? Round your answer to three decimal places.
Found 2 solutions by Edwin McCravy, vksarvepalli:
Answer by Edwin McCravy(20060)   (Show Source):
You can put this solution on YOUR website! A fair die is rolled 6 times. What is the probability of having no 1 and no 2 among the rolls?
The probability of getting a 3, 4, 5 or 6 the 1st time is 4 ways out of 6, which is  or 
multiplied by
the probability of getting a 3, 4, 5 or 6 the 2nd time, or
multiplied by
the probability of getting a 3, 4, 5 or 6 the 3rd time, or
multiplied by
the probability of getting a 3, 4, 5 or 6 the 4th time, or
multiplied by
the probability of getting a 3, 4, 5 or 6 the 5th time, or
multiplied by
the probability of getting a 3, 4, 5 or 6 the 6th time, or
So it's  or about .088
Edwin
Answer by vksarvepalli(154)  (Show Source):
You can put this solution on YOUR website! when a fair die is rolled once the probability of a particular number to come is 1/6
now the die is rolled 6 times and we need to have no 1 and no 2 among the rolls
so out of any 6 outcomes the required no.s can come
so the no. of ways of those two outcomes is 6C2 = 15
so the probability of no 1 and no 2 coming in these two outcomes is
15*(1/6)*(1/6)=15/36= 0.416666 = 0.417 Answer
|
|
|
