Question 26593: I'm suppose to find the equation of each line and write the equation using function notation:
heres the problem:
through (-4,8); perpendicular to 2x-3y=1
heres the work i have done:
-3y = -2x+1 y=2/3x +1/3
slope = 2/3
y-8 = 2/3(x+4)
y+-8= 2/3x + 2 2/3
y=2/3x+-5 1/3
f(x)= 2/3x + -5 1/3
did i do this problem right or am i doing it completely wrong, please help, thanks
Answer by Alwayscheerful(414) (Show Source):
You can put this solution on YOUR website! Here's what I would do:
First, I would find the slope (which you did right)
The slope is 
The work you did found the line that went through (-4,8), but wasn't perpendicular to . That was your mistake.
To find a perpendicular line, the slope will be the negative reciprocal.
So, the slope of your line will be .
To find the y-intercept, the easiest way is to plug the coordinates you already have back into slope-intercept form, which is .

Solved by pluggable solver: EXPLAIN simplification of an expression |
Your Result:
YOUR ANSWER
- This is an equation! Solutions: b=2.
- Graphical form: Equation
was fully solved. - Text form: 8=(-3/2)*-4+b simplifies to 0=0
- Cartoon (animation) form:
For tutors: simplify_cartoon( 8=(-3/2)*-4+b )
- If you have a website, here's a link to this solution.
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DETAILED EXPLANATION
Look at . Remove unneeded parentheses around factor , It becomes .
Look at . Multiplied numerator integers It becomes .
Look at . Moved to the right of expression It becomes .
Look at . Removed extra sign in front of  It becomes .
Look at . Moved these terms to the left , It becomes .
Look at . Added fractions or integers together It becomes .
Look at . Moved to the right of expression It becomes .
Look at . Solved linear equation equivalent to -b+2 =0 It becomes . Result: 
This is an equation! Solutions: b=2.
Universal Simplifier and Solver
Done!
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So, you find that your y-intercept is 2.
The final formula in function notaion would be 
To check, graphing it may be helpful.

The GREEN line is the original, and the RED line is the one you were trying to solve for.
From the graph, you can indeed see that the lines are parrallel.
Hope this helps!
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