SOLUTION: On a test, a student must answer any 7 of the first 10 questions and any 5 of the second 8 questions. In how many ways can this be done? Please help. Thank you.

Algebra ->  Probability-and-statistics -> SOLUTION: On a test, a student must answer any 7 of the first 10 questions and any 5 of the second 8 questions. In how many ways can this be done? Please help. Thank you.      Log On


   



Question 265870: On a test, a student must answer any 7 of the first 10 questions and any 5 of the second 8 questions. In how many ways can this be done? Please help. Thank you.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
On a test, a student must answer any 7 of the first 10 questions and any 5 of the second 8 questions. In how many ways can this be done? Please help. Thank you.
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ways to select 7 of 10: 10C7 = 10C3 = 120
ways to select 5 of 8: 8C5 = 8C3 = 56
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Total # of ways 56*120 = 6720
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Cheers,
Stan H.