SOLUTION: A rectangle is 2 times as long as it is wide. If the area is 50 square feet, find its perimeter.

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: A rectangle is 2 times as long as it is wide. If the area is 50 square feet, find its perimeter.       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 265852: A rectangle is 2 times as long as it is wide. If the area is 50 square feet, find its perimeter.
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
A rectangle is 2 times as long as it is wide. If the area is 50 square feet, find its perimeter.
____
first off Perimeter(P)= 2 Length(L) + 2 Width(W)
P=2L+2W
and Area(A)=Langth(L) times Width(W)
A=LW
____
so A=50 and L=2W
.
A=LW
50=2W%28W%29%0D%0A%7B%7B%7B50%2F2=2%2F2%28W%5E2%29
sqrt%2825%29=sqrt%28W%5E2%29
5=W
L=2W
L=2%285%29
L=10
P=2L+2W
P=2%2810%29%2B2%285%29
P=%2820%2B10%29
P=30