SOLUTION: I just wanted to make sure I am doing division of polynomials is correct. {{{(x^2-3)/(x-2)}}}= {{{x+1/(x-2)}}}

The numerator has a missing power of ,

so we must write it 

            x + 2
x - 2)x² + 0x - 3
      x² - 2x
           2x - 3
           2x - 4
                1

Answer:  

Edwin