SOLUTION: what is the smallest of three positive consecutive odd integers if the product of the second and third integers is 63?

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Question 265706: what is the smallest of three positive consecutive odd integers if the product of the second and third integers is 63?
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Let x, x+2, x+4 be the three integers
from above, we get
%28x%2B2%29%28x%2B4%29+=+63
by foiling, we get
x%5E2+%2B+6x+%2B+8+=+63
subtracting, we get
x%5E2+%2B+6x+-+55+=+0
factoring, we get
%28x%2B11%29%28x-5%29+=+0
solving, we get
x = -11 and x = 5
since we want positive, we get
5, 7, 9