SOLUTION: Write the equation in standard form of the line satisfying the given conditions. Through (-2,4); m= -3/4 I'm assuming you use point-slope form. y-y1= m(x-x1) But I came up

Algebra ->  Linear-equations -> SOLUTION: Write the equation in standard form of the line satisfying the given conditions. Through (-2,4); m= -3/4 I'm assuming you use point-slope form. y-y1= m(x-x1) But I came up       Log On


   



Question 265553: Write the equation in standard form of the line satisfying the given conditions. Through (-2,4); m= -3/4
I'm assuming you use point-slope form. y-y1= m(x-x1)
But I came up with a different answer than the book. The book says the answer is 3x+4y=10
How do you get that answer?

Found 2 solutions by Alan3354, josmiceli:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Write the equation in standard form of the line satisfying the given conditions. Through (-2,4); m= -3/4
I'm assuming you use point-slope form. y-y1= m(x-x1)
But I came up with a different answer than the book. The book says the answer is 3x+4y=10
How do you get that answer?
------------
Find b
y = mx + b
4 = (-3/4)*(-2) + b
4 = 3/2 + b
b = 5/2
-----------
--> y = (-3/4)x + 5/2
4y = -3x + 10
3x + 4y = 10

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29
y%5B1%5D+=+4
x%5B1%5D+=+-2
m+=+-%283%2F4%29
y+-+4+=+-%283%2F4%29%2A%28x+-+%28-2%29%29
(note that (-)*(-)*(-) = (-))
y+-+4+=+-%283%2F4%29%2Ax+-+%283%2F4%29%2A2
y+-+4+=+-%283%2F4%29%2Ax+-+3%2F2
4y+-+16+=+-3x+-+6
4y+=+-3x+%2B+10
3x+%2B+4y+=+10