Question 265176: jen is 6 years older than sue. in 4 years, she will be twice as old as sue was 5 years ago. Find their ages now Found 2 solutions by palanisamy, dabanfield:Answer by palanisamy(496) (Show Source):
You can put this solution on YOUR website! Let the age of Sue = x
Then the age of Jen = x+4
Given,in 4 years, Jen will be twice as old as sue was 5 years ago.
x+4+4 = 2(x-5)
x+8 = 2x-10
8+10 = 2x-x
18 = x
x = 18
So, the age of Sue = 18
and the age of Jen = x+4 = 18+4 = 22
You can put this solution on YOUR website! jen is 6 years older than sue. in 4 years, she will be twice as old as sue was 5 years ago. Find their ages now
Let J be Jen's age and S Sue's age. Then:
1.) J = S + 6
2.) J + 4 = 2*(S - 5)
Substitute S + 6 from 1.) for J in 2.):
(S + 6) + 4 = 2*(S - 5)
Solve the above for S then calculate J = S + 6.
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