SOLUTION: I hope that I can describe this well enough. I have a problem with a graph that contains two parallel lines. Line 1 has the equation y=2x+1 and Line 2 contains the point (0,-2).

Algebra ->  Graphs -> SOLUTION: I hope that I can describe this well enough. I have a problem with a graph that contains two parallel lines. Line 1 has the equation y=2x+1 and Line 2 contains the point (0,-2).       Log On


   

Question 264733: I hope that I can describe this well enough. I have a problem with a graph that contains two parallel lines. Line 1 has the equation y=2x+1 and Line 2 contains the point (0,-2). The problem is asking me to find point P in Line 2. What I know is that P is (?, 0). I've tried (4,0), but the computer program I'm working with doesn't like that answer. Any help would be greatly appreciated!
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Any 2 lines that are parallel have the same slope.
The 1st line, y+=+2x+%2B+1, is in the form
y+=+mx+%2B+b,
where m is the slope, so
the slope of both lines must be 2
given:
Line 2 goes through (0,-2)
I can plug this (x,y) into y+=+mx+%2B+b, m+=+2
and I can find b
-2+=+2%2A0+%2B+b
b+=+-2
Now I know line 2 is y+=+2x+-+2
Now I can find (x,0)
0+=+2x+-+2
2x+=+2
x+=+1
So the point asked for is P(1,0)