SOLUTION: solve by eilimination 1)3x+7y =48 5x-7y= -32 2)-2x+3y =25 -2x+6y=58 3)3x+8y = 81 5x+6y=-39 4)8x+13y=179 2x-13y=-69

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: solve by eilimination 1)3x+7y =48 5x-7y= -32 2)-2x+3y =25 -2x+6y=58 3)3x+8y = 81 5x+6y=-39 4)8x+13y=179 2x-13y=-69      Log On


   



Question 264711: solve by eilimination
1)3x+7y =48
5x-7y= -32
2)-2x+3y =25
-2x+6y=58
3)3x+8y = 81
5x+6y=-39
4)8x+13y=179
2x-13y=-69

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!

I'll just do the 3rd one, the hardest one:

system%283x%2B8y+=+81%2C5x%2B6y=-39%29

To eliminate the x's:

The coefficients of x are 3 and 5.
The least common multiple of 3 and 5 is 15. We want to
make one of the coefficients of x 15 and the other one
-15.  To do that we multiply the first equation through
by 5 and the second one through by -3:

system%2815x%2B40y=405%2C-15x-18y=117%29

Add the two equations term by term
 
0x%2B22y=522
22y=522
y=522%2F22
y=261%2F11

Go back to the original system:

system%283x%2B8y+=+81%2C5x%2B6y=-39%29

To eliminate the y's:
The coefficients of y are 8 and 6.
The least common multiple of 8 and 6 is 24. We want to
make one of the coefficients of y 24 and the other one
-24.  To do that we multiply the first equation through
by 3 and the second one through by -4:

system%289x%2B24y=243%2C-20x-24y=156%29

Add the two equations term by term
 
-11x%2B0y=399

-11x=399

x=-399%2F11

Edwin