Question 26468: find an equation in slope-intercept form (where possible)
Through (-1,4), parallel to x + 3y = 5
Answer by algebrawiz(2)   (Show Source):
You can put this solution on YOUR website! 1. Since the problem says the equation is parallel to x + 3y = 5. It is true that the slopes are equal, so lets find the slope(m) of the given equation:
a. solve for y:
x + 3y = 5 subtact x from both sides
3y = -x + 5 (I switched the position from 5-x, but the signs are correct)now divide both sides by 3
y= (-x/3)+(5/3) so m=-1/3
2. Now that we've found the slope(-1/3) and we have a point(-1,4) we can use the point-slope equation. Lets do this:
a. y-y1=m(x-x1) (point-slope) plug in the m,y1,and x1
b. y-(4)= (-1/3)(x-(-1)) do the math
c. y-4 = -x/3 + (1/3) add 4 to both sides
so the equation is y = -x/3 + 11/3
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