SOLUTION: A chemist has one solution that is 60% chlorinated and another solution that is 40% chlorinated. How much of the first (60%) solution is needed to make a 100 L solution that is 50%

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Question 264489: A chemist has one solution that is 60% chlorinated and another solution that is 40% chlorinated. How much of the first (60%) solution is needed to make a 100 L solution that is 50% chlorinated?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A chemist has one solution that is 60% chlorinated and another solution that is 40% chlorinated. How much of the first (60%) solution is needed to make a 100 L solution that is 50% chlorinated?
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Equation:
chlorine + chlorine = chlorine
0.60x + 0.40(100-x) = 0.50*100
Multiply thru by 100 to get:
60x + 40*100 - 40x = 50*100
20x = 10*100
x = 50 L (amount of 60% solution needed in the mixture)
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Cheers,
Stan H.