SOLUTION: jack is thinking of 2 positive numbers. One of them is 4 more than the other, and the sum of their squares is 208. What are the numbers?

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: jack is thinking of 2 positive numbers. One of them is 4 more than the other, and the sum of their squares is 208. What are the numbers?      Log On


   



Question 264422: jack is thinking of 2 positive numbers. One of them is 4 more than the other, and the sum of their squares is 208. What are the numbers?
Answer by vksarvepalli(154) About Me  (Show Source):
You can put this solution on YOUR website!
let the two positive no.s be x & y
given x=4+y
and x^2 + y^2 = 208
that is (4+y)^2 + y^2 = 208
=> 16%2B8y%2By%5E2%2By%5E2=208
=> 2y^2+8y-192=0
=>2(y^2+4y-96)=0
=>y^2+4y-96=0
=>y^2+12y-8y-96=0
=>y(y+12)-8(y+12)=0
=>(y-8)(y+12)=0
so y=8 , -12
so x=12 , -8
so the no.s are (8,12) or (-12,-8)