SOLUTION: The time needed to complete the final examination of MGSC 301 is normally distributed with a mean of 120 minutes and a standard deviation of 12 minutes.
a.
What is the probabil
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-> SOLUTION: The time needed to complete the final examination of MGSC 301 is normally distributed with a mean of 120 minutes and a standard deviation of 12 minutes.
a.
What is the probabil
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Question 264417: The time needed to complete the final examination of MGSC 301 is normally distributed with a mean of 120 minutes and a standard deviation of 12 minutes.
a.
What is the probability that a student will finish the examination in two hours or more?
b.
What is the probability that a student will finish the examination in more than 100 minutes but less than 150 minutes?
c.
What is the probability that a student will finish the examination in more than 140 minutes?
You can put this solution on YOUR website! The time needed to complete the final examination of MGSC 301 is normally distributed with a mean of 120 minutes and a standard deviation of 12 minutes.
a.
What is the probability that a student will finish the examination in two hours or more?
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2 hrs is 120 minutes which is the mean.
P(x>= 120) = 0.5000
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b.
What is the probability that a student will finish the examination in more than 100 minutes but less than 150 minutes?
z(100) = (100-120)/12 = -20/12 = -1.667
z(150) = (150-120)/12 = 30/12 = 2.5
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P(100< x < 150) = P(-1.667 < z < 2.5) = 0.9460
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c.
What is the probability that a student will
finish the examination in more than 140 minutes?
z(140) = (140-120)/12 = 1.667
P(z > 140) = P(z> 1.667) = 0.0478
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Cheers,
Stan H.
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