SOLUTION: Write expression as a single log. log(base3)(squareroot ofx)- log(base 3) x^9

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Question 264255: Write expression as a single log. log(base3)(squareroot ofx)- log(base 3) x^9
Found 2 solutions by palanisamy, dabanfield:
Answer by palanisamy(496) About Me  (Show Source):
You can put this solution on YOUR website!
log(base3)(squareroot ofx)- log(base 3) x^9
= log(base3)(x^(1/2))- log(base 3) x^9
=(1/2)log(base3)x- 9log(base 3) x
=[(1/2)-9]log(base3)x
=-(17/2)log(base3)x

Answer by dabanfield(803) About Me  (Show Source):
You can put this solution on YOUR website!
Write expression as a single log. log(base3)(squareroot ofx)- log(base 3) x^9
1.) log(base3)(sqrt(x)) - log(base3)(x^9) =
2.) lob(base3) x^(1/2) - log(base3) (x^9)
Using the law log a - log b = log a/b we have:
3.) log(base3) x^(1/2) - log(base3)(x^9) =
4.) log(base3) x^(1/2)/x^9 = log(base3) x^(1/2 - 9) =
5.) log(base3)x^(-17/2)