SOLUTION: please help me solve this using substitution, I don't understand how to work any of these linear equations by substitution or elimination. x + 3y = 3 2x + 3y = 0

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Question 26398: please help me solve this using substitution, I don't understand how to work any of these linear equations by substitution or elimination.
x + 3y = 3
2x + 3y = 0
Answer by Alwayscheerful(414) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++1%5Cx+%2B+3%5Cy+=+3%2C%0D%0A++++2%5Cx+%2B+3%5Cy+=+0+%29%0D%0A++We'll use substitution. After moving 3*y to the right, we get:
1%2Ax+=+3+-+3%2Ay, or x+=+3%2F1+-+3%2Ay%2F1. Substitute that
into another equation:
2%2A%283%2F1+-+3%2Ay%2F1%29+%2B+3%5Cy+=+0 and simplify: So, we know that y=2. Since x+=+3%2F1+-+3%2Ay%2F1, x=-3.

Answer: system%28+x=-3%2C+y=2+%29.

OR
Solved by pluggable solver: Linear System solver (using determinant)
Solve:
+system%28+%0D%0A++++1%5Cx+%2B+3%5Cy+=+3%2C%0D%0A++++2%5Cx+%2B+3%5Cy+=+0+%29%0D%0A++

Any system of equations:


has solution

or



(x=-3, y=2}

Hope this helps!