SOLUTION: s^2 = t^-1 and t^1/4 = u^-1/3, then what is the value of s in terms of u?

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Question 263906: s^2 = t^-1 and t^1/4 = u^-1/3, then what is the value of s in terms of u?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
s^2 = t^-1 and t^1/4 = u^-1/3, then what is the value of s in terms of u
:
s%5E2+=+t%5E-1
Reciprocal gets rid of the neg exponent
s%5E2+=+1%2Ft
then
s+=+sqrt%281%2Ft%29
:
:
t%5E%281%2F4%29+=+u%5E%28-1%2F3%29
Raise both side to the 4th power
t+=+u%5E%28-4%2F3%29; (this is -4/3 power)
:
Replace t in s+=+sqrt%281%2Ft%29
s+=+sqrt%281%2Fu%5E%28-4%2F3%29%29%29
Reciprocal gets rid of the neg exponent
s+=+sqrt%28u%5E%284%2F3%29%29%29
We can also write the square root like this
s+=+u%5E%28%284%2F3%29%2A%281%2F2%29%29
which is
s+=+u%5E%282%2F3%29%29; (exponent is 2/3)