SOLUTION: Art works in a small retail store that sells widgets. Market research shows that red is, by far, the most popular color of widget, and that 38% of customers purchase red widgets. I

Algebra ->  Probability-and-statistics -> SOLUTION: Art works in a small retail store that sells widgets. Market research shows that red is, by far, the most popular color of widget, and that 38% of customers purchase red widgets. I      Log On


   



Question 263759: Art works in a small retail store that sells widgets. Market research shows that red is, by far, the most popular color of widget, and that 38% of customers purchase red widgets. If Art selects 5 random customers and records the color of widget purchased, what is the probability that at least one of those customers purchased a red widget?
What I did was take .38 x .38= .1444 and then add .1444 to .38. I got .5244, then multiplied that by .38. I then added this new number to .38 and got .579272, I kept doing this until I got 0.6080468. I don't know if this is right so I need help.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Art works in a small retail store that sells widgets. Market research shows that red is, by far, the most popular color of widget, and that 38% of customers purchase red widgets. If Art selects 5 random customers and records the color of widget purchased, what is the probability that at least one of those customers purchased a red widget?
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P(at least one of anything) = 1 - P(none of anything)
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Your Problem:
P(none of the 5 purchased a red widget) = (0.62)^5 = 0.0916
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So, P(at least one pruchased a red widget + 1 - 0.0916 = 0.9084
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Cheers,
Stan H.





What I did was take .38 x .38= .1444 and then add .1444 to .38. I got .5244, then multiplied that by .38. I then added this new number to .38 and got .579272, I kept doing this until I got 0.6080468. I don't know if this is right so I need help.