SOLUTION: 6x^3+54x^2+120x=0 using x=y^2

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Question 263572: 6x^3+54x^2+120x=0
using x=y^2
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Here is the original problem
6x%5E3%2B54x%5E2%2B120x=0+
step 1 - factor out 6x to get
6x%28x%5E2+%2B+9x+%2B+20%29+=+0
step 2 - factor the trinomial to get
6x%28x%2B4%29%28x%2B5%29+=+0
step 3 - set each part = 0 and solve to get
x = 0
x = -4
x = -5
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not sure why you would use x=y^2 to solve this question.