SOLUTION: Ellen wishes to mix candy worth $1.80 per pound with candy worth $2.40 per pound to form 48 pounds of a mixture worth $2.00 per pound. How many pounds of the more expensive candy s

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Ellen wishes to mix candy worth $1.80 per pound with candy worth $2.40 per pound to form 48 pounds of a mixture worth $2.00 per pound. How many pounds of the more expensive candy s      Log On


   

Question 263564: Ellen wishes to mix candy worth $1.80 per pound with candy worth $2.40 per pound to form 48 pounds of a mixture worth $2.00 per pound. How many pounds of the more expensive candy should she use?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Ellen wishes to mix candy worth $1.80 per pound with candy worth $2.40 per pound to form 48 pounds of a mixture worth $2.00 per pound. How many pounds of the more expensive candy should she use?
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Equation:
value + value = value
1.8x + 2.4(48-x) = 2*48
Multiply thru by 10 to get:
18x + 24*48 - 24x = 20*48
-6x = -4*48
x = 4*8 = 32 (amount of $1.80 candy needed in the mixture)
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48-32 = 16 lbs (amount of $2.40 candy needed in the mixture)
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Cheers,
Stan H.