SOLUTION: 5 liters of a 4 % solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10 % solution must be added.

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Question 263559: 5 liters of a 4 % solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10 % solution must be added.
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
We have a mixture problem. Here is a table based on the given information
solution . . . . . . . % . . . . . . . .L . . . . . . . . . %L
4% . . . . . . . . . . . 4 . . . . . . . 5 . . . . . . . . . .20
10% . . . . . . . . . . 10 . . . . . . x . . . . . . . . .10x
6% . . . . . . . . . . . 6 . . . . . . .x + 5 . . . . . . 6x + 30
look at column three, we get
20+%2B+10x+=+6x+%2B+30
subtract 6x and subtract 20 to get
4x+=+10
so,
x+=+2.5
you need 2.5 liters @ 10%.