SOLUTION: find the vertex of f(x)=(1/4)x^2

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Question 263545: find the vertex of f(x)=(1/4)x^2
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
quadratics are of the form
y+=+a%28x-h%29%5E2+%2B+k
were h , k is the vertex
we are given
f%28x%29=%281%2F4%29x%5E2
or
f%28x%29+=+%281%2F4%29%28x-0%29%5E2+%2B+0
the vertex is at (0,0)