SOLUTION: a coin bank containe nickels, dimes, and quarters totaling $5.45. If there are twice as many quarters as dimes and 11 more nickels than quarters, how many of each coin are in the
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Question 263481: a coin bank containe nickels, dimes, and quarters totaling $5.45. If there are twice as many quarters as dimes and 11 more nickels than quarters, how many of each coin are in the bank? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! Q=2D OR D=Q/2
N=Q+11
N+D+Q=5.45
.05N+.10D+.25Q=5.45
.05(Q+11)+.10(Q/2)+.25Q=5.45
.05Q+.55+.05Q+.25Q=5.45
.35Q=5.45-.55
.35Q=4.90
Q=4.90/.35
Q=14 QUARTERS.
N=14+11=25 NICKELS
D=14/2=7 DIMES
PROOF:
.05*25+.10*7+.25*14=5.45
1.25+.70+3.50=5.45
5.45=5.45
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