SOLUTION: On the first part of a trip Bob averaged 60mph but on the second part of the trip, which was 50 miles more than the first part, he averaged 40mph. What was the total distance for t

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: On the first part of a trip Bob averaged 60mph but on the second part of the trip, which was 50 miles more than the first part, he averaged 40mph. What was the total distance for t      Log On

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Question 263345: On the first part of a trip Bob averaged 60mph but on the second part of the trip, which was 50 miles more than the first part, he averaged 40mph. What was the total distance for the trip if the entire trip took 8 hours?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
60x=y and
40*(8-x)=50+y and
z=2y+50
z=374
trip was 374 miles