SOLUTION: An object is thrown downward from a plane which is 540 feet above the ground. The object is thrown with an initial velocity of 27 ft/sec. The distance traveled by the object in t s
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Question 263334: An object is thrown downward from a plane which is 540 feet above the ground. The object is thrown with an initial velocity of 27 ft/sec. The distance traveled by the object in t seconds is s = 16t2 + 27t, where s is in feet. How long does it take the object to reach the ground?
You can put this solution on YOUR website! An object is thrown downward from a plane which is 540 feet above the ground. The object is thrown with an initial velocity of 27 ft/sec. The distance traveled by the object in t seconds is s = 16t2 + 27t, where s is in feet. How long does it take the object to reach the ground?
First, determine how long it will take to fall to the ground.
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Given:
s = 16t^2 + 27t
Set s to 540 and solve
540 = 16t^2 + 27t
0 = 16t^2 + 27t - 540
Solve using the quadratic equation. Doing so, yields:
t = {5.0, -6.7}
Throw out the negative answer leaving:
t = 5 seconds
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Details of the quadratic equation to follow: