Question 263144: The production manager at Bellevue Steel, a manufacturer of wheelchairs, wants to compare the number of defective wheelchairs produced on the day shift with the number on the afternoon shift. A sample of the production from 6 day shifts and 8 afternoon shifts revealed the following number of defects. Assume this is a two sample “Unknown Variances, Assumed Equal”. The level of significance is 0.05. The standard deviation for Day is 1.4142 and the standard deviation for Afternoon is 2.2678.
Day 5 8 7 6 9 7
Afternoon 8 10 7 11 9 12 14 9
1. Set up the null and alternative hypothesis.
2. Calculate the value of the test statistic.
3. What is the value of the test statistic?
4. What is the decision rule (DR)?
5. Reject Ho if (complete the DR in next box)
6. What is your decision regarding Ho?
Accept or Reject Ho?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The production manager at Bellevue Steel, a manufacturer of wheelchairs, wants to compare the number of defective wheelchairs produced on the day shift with the number on the afternoon shift.
A sample of the production from 6 day shifts and 8 afternoon shifts revealed the following number of defects. Assume this is a two sample “Unknown Variances, Assumed Equal”. The level of significance is 0.05. The standard deviation for Day is 1.4142 and the standard deviation for Afternoon is 2.2678.
Day:::::: 5 8 7 6 9 7
Afternoon 8 10 7 11 9 12 14 9
1. Set up the null and alternative hypothesis.
Ho: u(day)-u(aft) = 0
Ha: u(day)-u(aft) is not equal to 0
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2. Calculate the value of the test statistic.
I ran a 2-Sample Ttest and got:
t = -3.0363...
3. What is the critical value
If alpha = 5% cv = +-invT(0.025,df = 12) = +-2.1788
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4. What is the decision rule (DR)?
Reject Ho if the test stat is > 2.1788 or <-2.1788
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5. Reject Ho if (complete the DR in next box)
6. What is your decision regarding Ho?
Accept or Reject Ho?
Reject Ho.
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Cheers,
Stan H.
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