Question 263086: Translate the problem into a pair of linear equations in two vaiables. Solve the equations using either elimination or substitution. State your answer for the specified variable.
Tim and Judy mix two kinds of feed for pedigreed dogs. They wish to make 54 pounds of feed worth $0.28 per pound by mixing one kind worth $0.24 per pound with another worth $0.42 per pound. How many pounds of the cheaper kind should they use in the mix?
I just need to know what the two linear problems are, I can finish the problem from there. I just can't figure out how to get two problems from this. Thanks!
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Tim and Judy mix two kinds of feed for pedigreed dogs.
They wish to make 54 pounds of feed worth $0.28 per pound by mixing one kind worth $0.24 per pound with another worth $0.42 per pound.
How many pounds of the cheaper kind should they use in the mix?
:
Let x = amt of .24/lb required (the cheaper kind)
Let y = amt of .42/lb required
;
The total pounds equation
x + y = 54
which is
y = (54-x), use this for substitution
:
The total cost/lb equation
.24x + .42y = .28(54)
.24x + .42y = 15.12
:
You should be able solve this by substituting (54-x) for y in the above equation
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