SOLUTION: A square with side length s is inscribed as in an equilateral triangle with side length t. What is the ratio t : s? Express your answer as a decimal to the nearest thousandth.

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Question 262990: A square with side length s is inscribed as in an equilateral triangle with side length t. What is the ratio t : s? Express your answer as a decimal to the nearest thousandth.
Answer by Edwin McCravy(20086) About Me  (Show Source):
You can put this solution on YOUR website!

Let the equilateral triangle be ABC, and the
inscribed square be DEFG:



We draw in the green median CH from vertex C to the bottom
side AB, which is also the perpendicular bisector of AB,
and also the bisector of the angle C.



We find the length of CH by the Pythagorean theorem

AC+=+t, AH+=+t%2F2

AC%5E2=AH%5E2%2BCH%5E2
t%5E2=%28t%2F2%29%5E2%2BCH%5E2
t%5E2=t%5E2%2F4%2BCH%5E2
4t%5E2=t%5E2%2B4%2ACH%5E2
3t%5E2=4%2ACH%5E2
%283t%5E2%29%2F4=CH%5E2
sqrt%28%283t%5E2%29%2F4%29=sqrt%28CH%5E2%29
%28t%2Asqrt%283%29%29%2F2=CH

Triangle ADG is similar to triangle AHC,

so %28GD%29%2F%28AD%29=%28CH%29%2F%28AH%29

AH+=t%2F2, DH=s%2F2, so

AD=AH-DH=t%2F2-s%2F2=%28t-s%29%2F2 

GD=s, CH=%28t%2Asqrt%283%29%29%2F2

Substitute in

%28GD%29%2F%28AD%29=%28CH%29%2F%28AH%29

s%2F%28%28t-s%29%2F2%29=%28%28t%2Asqrt%283%29%29%2F2%29%2F%28t%2F2%29

Multiply tops and bottoms of the fractions on both
sides by 2.

%282s%29%2F%28t-s%29=%28t%2Asqrt%283%29%29%2Ft   

Cancel t's on the right sides:

%282s%29%2F%28t-s%29=sqrt%283%29

Multiply both sides by %28t-s%29

2s=sqrt%283%29%28t-s%29

2s=sqrt%283%29t-sqrt%283%29s

2s%2Bsqrt%283%29s=sqrt%283%29t

factor out s on the left:

s%282%2Bsqrt%283%29%29=sqrt%283%29t

Divide both sides by s%2Asqrt%283%29

%282%2Bsqrt%283%29%29%2Fsqrt%283%29=t%2Fs

Punching the left side out on a calculator

t%2Fs=2.154700538

To the nearest thousandth, 

t%2Fs=2.155

Edwin