SOLUTION: 2r+3s=0 r+5=6s

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Question 26291: 2r+3s=0 r+5=6s
Answer by Alwayscheerful(414) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Linear System solver (using determinant)
Solve:
+system%28+%0D%0A++++2%5Cr+%2B+3%5Cs+=+0%2C%0D%0A++++1%5Cr+%2B+-6%5Cs+=+-5+%29%0D%0A++

Any system of equations:


has solution

or



(r=-1, s=0.666666666666667}

OR

Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++2%5Cr+%2B+3%5Cs+=+0%2C%0D%0A++++1%5Cr+%2B+-6%5Cs+=+-5+%29%0D%0A++We'll use substitution. After moving 3*s to the right, we get:
2%2Ar+=+0+-+3%2As, or r+=+0%2F2+-+3%2As%2F2. Substitute that
into another equation:
1%2A%280%2F2+-+3%2As%2F2%29+%2B+-6%5Cs+=+-5 and simplify: So, we know that s=0.666666666666667. Since r+=+0%2F2+-+3%2As%2F2, r=-1.

Answer: system%28+r=-1%2C+s=0.666666666666667+%29.

Hope this helps!