Question 262830: Find an equation of the perpendicular bisector of the lina segment AB;A(2,1)B(-2,3)
Found 2 solutions by Alan3354, drk:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Find an equation of the perpendicular bisector of the lina segment AB;
A(2,1)B(-2,3)
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Find the midpoint by getting the averages of x and y separately.
x: (2-2)/2 = 0
y: (1+3)/2 = 2
M is (0,2)
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Find the slope, m, of AB
m = diffy/diffx = (3-1)/(-2-2)
m = -1/2
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The slope of lines perpendicular is the negative inverse, = +2
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Use y = mx + b and the point M to find b
2 = 2*0 + b
b = 2
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--> y = 2x + 2
Answer by drk(1908)  (Show Source):
You can put this solution on YOUR website! step 1 - find the midpoint of the coordinates. We get
mp = ((2-2)/2, (1+3)/2)
mp = (0, 2))
step 2 - find the slope as
m = (3-1)/(-2-2) = 2/-4 = -1/2
we want the perpendicular slope so we take the negative flip of this to get
m = 2
step 3 - write the equation as
y-2 = 2(x-0)
or
y = 2x + 2
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