SOLUTION: find the dimensions of a rectangle whose perimeter is 52 inches if the length is 5 inches more than twice the width
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Question 262714: find the dimensions of a rectangle whose perimeter is 52 inches if the length is 5 inches more than twice the width Answer by vksarvepalli(154) (Show Source):
You can put this solution on YOUR website! let the width be x inches
so the length will be 5+2x
now given, perimeter=52 inches
perimeter of a rectangle = twice sum of length and width
so 2(5+2x+x)=52
=> 5+3x=26
=> 3x=21
=> x=7
then 5+2x will be 5+14=19
so the length is 19 inches
and the width 7 inches
