SOLUTION: Find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer.

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Question 262512: Find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer.
Answer by dabanfield(803) About Me  (Show Source):
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Find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer.
Let x be the smallest of the three consecuticve even integers. Then the second and third integers are x+2 and x+4 respectively.
Then we have:
(x+2)*(x+4) = 10*x + 20
Solve the above for x and then calculate x+2 and x+4.