SOLUTION: 1) Myrna is 27 years older than her son. A year ago, she was twice as old as him. How old is Myrna now? 2) The sum of two numbers is 574. One number is six times the other. Find

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Question 262404: 1) Myrna is 27 years older than her son. A year ago, she was twice as old as him. How old is Myrna now?
2) The sum of two numbers is 574. One number is six times the other. Find the larger number.
3) The sum of two numbers is 56. Their difference is 22. Find the larger number.
4) The sum of two numbers is 1457. Four times the first number minus twice the second number is 8. Find the larger number.
Found 2 solutions by richwmiller, drk:
Answer by richwmiller(17219) (Show Source):
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m=27+s
(m-1)=2(s-1)
substituting 27+s for m
27+s-1=2s-2

Answer by drk(1908) (Show Source):
You can put this solution on YOUR website!
1) Myrna is 27 years older than her son. A year ago, she was twice as old as him. How old is Myrna now?
answer - - >
M = S + 27
M-1 = 2*(S-1)
S+27-1 = 2S - 2
S + 26 = 2S - 2
28 = S
M = 55
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2) The sum of two numbers is 574. One number is six times the other. Find the larger number.
Answer -->
x + y = 574
x = 6y
6y + y = 574
7y = 574
y = 82
x = 492
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3) The sum of two numbers is 56. Their difference is 22. Find the larger number.
answer - - >
x + y = 56
x - y = 32
add down to get
2x = 88
x = 44
y = 12
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4) The sum of two numbers is 1457. Four times the first number minus twice the second number is 8. Find the larger number.
answer -- >
x + y = 1457
4x - 2y = 8
multiply first equation by 2 to get
2x - 2y = 2914
add second and third to get
6x = 2922
divide to get
x = 487
y = 970