SOLUTION: I need help on finding an equation for this problem: A 29 inch rope is cut into 3 pieces, the middle sized piece is 1 inch longer than the shorter piece and the longest piece is tw
Question 262355: I need help on finding an equation for this problem: A 29 inch rope is cut into 3 pieces, the middle sized piece is 1 inch longer than the shorter piece and the longest piece is twice as long as the short piece. How long is each piece? Found 2 solutions by solver91311, ptaylor:Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!
Let represent the short piece. Then the middle-sized piece is and the long piece is . The measures of the three pieces must add up to 29, so:
Solve for to get the measure of the short piece. Add 1 to get the measure of the middle piece and double the value of to get the measure of the long piece.
You can put this solution on YOUR website! OK.
Let x=the shorter piece
Then x+1=middle sized piece (we are told this)
And 2x=the longest piece (we are told this also)
And we know that the three pieces must add up to 29 inches. So our equation to solve is:
x+x+1+2x=29 collect like terms
4x+1=29 subtract 1 from each side
4x+1-1=29-1 collect like terms again
4x=28 divide each side by 4
x=7 in---------------shorter piece
x+1=7+1=8 in---------------middle sized piece
2x=2*7=14 in-----------------longest piece
CK
7+8+14=29
29=29
Hope this helps---ptaylor
