Question 262353: What is the equation of the line that passes through (6,-4)and (3,2)
Answer by EMStelley(208)   (Show Source):
You can put this solution on YOUR website! The first thing we need to determine here is the slope of the line. Remember that if you have two points (x1,y1) and (x2,y2), the slope is:
So here, (x1,y1) is (6,-4) and (x2,y2) is (3,2), so the slope is:
Now, remember that if you have a point (x1,y1) and a slope m, the equation of the line is:
y-y1 = m(x-x1)
So we have
y-(-4) = -2(x-6)
y+4 = -2x+12
y = -2x + 8
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