SOLUTION: Suppose the width of a certain rectangle is 1 inch more than 1/4 of its length. The perimeter of the rectangle is 72 inches find the length.
P=2L+2W
72=
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-> SOLUTION: Suppose the width of a certain rectangle is 1 inch more than 1/4 of its length. The perimeter of the rectangle is 72 inches find the length.
P=2L+2W
72=
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Question 262324: Suppose the width of a certain rectangle is 1 inch more than 1/4 of its length. The perimeter of the rectangle is 72 inches find the length.
P=2L+2W
72= Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! W=L/4+1
2L+2W=72
2L+2(L/4+1)=72
2L+L/2+2=72
2.5L=72-2
2.5L=70
L=70/2.5
L=28 ANS.
W=28/4+1
W=7+1=8 ANS.
PROOF:
2*28=2*8=72
56+16=72
72=72
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