Question 262317: determine the nature of the solutions of the equation
x^2+4=0
Please help me solve.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! determine the nature of the solutions of the equation
x^2+4=0
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It's a quadratic with a = 1, b = 0, c = 4
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The discriminant is b^2-4ac = 0^2 -4*1*4 = -16
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Since the discriminant is negative, the quadratic
has two unequal complex solutions.
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What are they:
x^2+4 = 0
Factor:
(x+2i)(x-2i) = 0
x = -2i or x = +2i
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Cheers,
Stan H.
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