Question 262216: ind three consecutive odd integers such that the product of the first and second exceeds the third by 8.
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! three consecutive odd integers such that the product of the first and second exceeds the third by 8
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Let x = first consecutive odd integer
then
x+2 = second consecutive odd integer
x+4 = third consecutive odd integer
.
x(x+2) = (x+4) + 8
x^2 + 2x = x + 12
x^2 +x -12 = 0
(x-3)(x+4) = 0
x = {3,-4}
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Since -4 is an even number toss out the solution.
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The three odd integers:
3,5,7
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