Question 26215: I've tried... believe me I have! ahhhhh! It seems so simple to most people, but this just wont go through my head! H-E-L-P please!
Side A of a triangle is tice side B. Side C is 2 meters shorter than side A. The perimeter is 98 meters. Help me find the length of each side please?
:-D thanks times a bajillion!
Answer by queenofit(120)   (Show Source):
You can put this solution on YOUR website! Ok first I will assume that when you said side A is tice side B, you meant twice, OK?. You need to know several things to find this answer. First, of course, you need the formula for the perimeter which is side +side +side. You have 3 sides. We will call them side A B and C. You know they equal 98 meters. now, to find the sides. First look at the question. The only variable you would have that does not have a number involved is your B side. So we will set up our equation as if we are solving for B, ok. this is what you know from the equation
B=B
A= 2B (side A is twice side B)
C=2B-2 (side C is 2 meters shorter than side A, which is 2B)
To get perimeter you add these three together and set them equal to 98
2B + B + 2B - 2 = 98 (do you see how I set A + B + C = 98)
5B-2=98 (combine like terms)
5B=100 (solve using algebra)
B=20 (side B = 20 meters)
A= 2*20=40 (side A= 40 meters)
C= 2*20-2=38 (side C = 38 meters)
check by adding A + B + C = 98
20+40+38=98
I hope this helps, if you need further assistance, please let me know.
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