Question 262110: find the perimeter of a rectangle ABCD with a side of 8 inches and a diagonal of 10 inches? Found 2 solutions by mananth, richwmiller:Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! find the perimeter of a rectangle ABCD with a side of 8 inches and a diagonal of 10 inches?
Let the other side be x
Side = 8 inches
Diagonal = 10 inches
10^2 = 8^2 + x^2 pythagoras
100-64=x^2
36=x^2
X=6
Perimeter = 2*(l+b)
=2(6+8)
=28 inches
mananth@hotmail.com
