SOLUTION: Write an equation and solve to find three consecutive integers whose sum is 33.

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Question 261902: Write an equation and solve to find three consecutive integers whose sum is 33.
Found 4 solutions by richwmiller, checkley77, Alan3354, solver91311:
Answer by richwmiller(17219)   (Show Source):
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The simple way is 33/3 =11 the middle one is 11
n+n+1+n+2=33
3n+3=33
3n=30
n=10
next two are 11 and 12

Answer by checkley77(12844)   (Show Source):
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X, X+1 & X+2 ARE THE 3 INTEGERS.
X+X+1+X+2=33
3X+3=33
3X=33-3
3X=30
X=10 THE FIRST INTEGER.
10+1=11 THE SECOND INTEGER.
10+2=12 THE THIRD INTEGER.
PROOF
10+11+12=33
33=33

Answer by Alan3354(69443)   (Show Source):
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33/3 = 11. That's the middle number.

Answer by solver91311(24713)   (Show Source):
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Let represent the first of the three consecutive integers. Then then next one has to be , and the one after that has to be . The sum means add them, so:

Solve for to find the first one, and the other two will be obvious.

John