Question 261836: two brothers,morris & martin are in their backyard.morris is taking down a wall on one side of the yard while martin is building a wall on the other side. martin starts from scratch and lays 2 bricks every minute. meanwhile, morris takes down 3 bricks each minute from his wall. it takes 55 minutes to finish tearing down his wall.how many bricks were originally in the wall morris was taking down? when did the walls have the same number of bricks?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! two brothers,morris & martin are in their backyard.morris is taking down a wall on one side of the yard while martin is building a wall on the other side. martin starts from scratch and lays 2 bricks every minute. meanwhile, morris takes down 3 bricks each minute from his wall. it takes 55 minutes to finish tearing down his wall.how many bricks were originally in the wall morris was taking down? when did the walls have the same number of bricks?
---
# of martin bricks = 2t where t is number of minutes he works.
----------------------
# of morris bricks = W - 3t where W is original number of bricks in Morris's wall
Morris takes 55 min to arrive at zero bricks, so:
W = -3(55) = -165 bricks (# of bricks taken down): 165 = original # of bricks.
------------------------------
When were # of bricks equal?
Solve 2t = 165
t = 82.5 minutes (Equal number of bricks after 82.5 minutes)
=============
Cheers,
Stan H.
|
|
|
