Question 261635: A sum of $113,000 is split between two investments, one paying 6% and the other 9%. If the total yearly interest amounted to $8550, how much was invested at 9%?
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! .09X+.06(113,000-X)=8,550
.09X+6,780-.06X=8,550
.03X=8,550-6,780
.03X=1,770
X=1,770/.03
X=59,000 ANS. FOR THE AMOUNT INVESTED @ 9%.
113,000-59,000=54,000
.09*59,000+.06*54,000=8,550
5,310+3,240=8,550
8,550=8,550
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