SOLUTION: HEIGHT OF A BULLET: HEIGHT OF A BULLET SHOT INTO THE AIR IS GIVEN BY s(t)= -4.9t^2+ 98t+2, WHERE t IS THE NUMBER OF SECONDS AFTER IT IS SHOT AND s(t) IS IN METERS.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: HEIGHT OF A BULLET: HEIGHT OF A BULLET SHOT INTO THE AIR IS GIVEN BY s(t)= -4.9t^2+ 98t+2, WHERE t IS THE NUMBER OF SECONDS AFTER IT IS SHOT AND s(t) IS IN METERS.       Log On


   

Question 261598: HEIGHT OF A BULLET: HEIGHT OF A BULLET SHOT INTO THE AIR IS GIVEN BY s(t)= -4.9t^2+ 98t+2, WHERE t IS THE NUMBER OF SECONDS AFTER IT IS SHOT AND s(t) IS IN METERS.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Stop yelling! Are the guns too loud for you?
BTW since you gave us no other details such as t then the height is s(t) or -4.9t^2+ 98t+2