SOLUTION: How do you solve this equation 5 times the first of 3 consecutive even integers is 14 more than 3 times the second. What is the third consecutive integer?

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Question 261431: How do you solve this equation 5 times the first of 3 consecutive even integers is 14 more than 3 times the second. What is the third consecutive integer?

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
LET X, X+2 & X+4 BE THE 3 CONSECUTIVE EVEN INTEGERS.
5X=3(X+2)+14
5X=3X+6+14
5X-3X=20
2X=20
X=20/2
X=10 THE FIRST INTEGER.
10+4=14 IS THE THIRD INTEGER.
PROOF:
5*10=3(10+2)+14
50=3*12+14
50=36+14
50=50