SOLUTION: d/dx ln(1/x^2-1)= (A) 1/x^2-1 (B) -2x/x^2-1 (C) 2x/x^2-1 (D) 2x^3-2x (E) 2x-2x^3

Algebra ->  Test -> SOLUTION: d/dx ln(1/x^2-1)= (A) 1/x^2-1 (B) -2x/x^2-1 (C) 2x/x^2-1 (D) 2x^3-2x (E) 2x-2x^3      Log On


   

Question 261421: d/dx ln(1/x^2-1)=
(A) 1/x^2-1
(B) -2x/x^2-1
(C) 2x/x^2-1
(D) 2x^3-2x
(E) 2x-2x^3
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Hint: Use the chain rule by letting u=1%2F%28x%5E2-1%29 and derive ln%28u%29 (with respect to x) to get %281%2Fu%29%2A%28du%2Fdx%29


Note: du%2Fdx is the derivative of 'u' with respect to 'x'.