SOLUTION: Ten percent of all people are left handed. If two people are randomly selected, what is the probability of getting one left handed person and one right handed person?
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-> SOLUTION: Ten percent of all people are left handed. If two people are randomly selected, what is the probability of getting one left handed person and one right handed person?
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Question 261317: Ten percent of all people are left handed. If two people are randomly selected, what is the probability of getting one left handed person and one right handed person? Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! probability of a person being left handed is 10% = .1
probability of a person being right handed is 1 - .1 = .9
p(1 left and 1 right) = .1*.9 * 2 = .18
you multiply by 2 because it can happen in 2 ways.
first way is you pick the first person who is left handed and then you pick the second person who is right handed.
second way is you pick the first person who is right handed and then you pick the second person who is left handed.
total possibilities are 0 left and 2 right, 1 left and 1 right, 2 left and 0 right.
p(0 left and 2 right) = .9^2 = .81
p(1 left and 1 right) = .1 * .9 * 2 = .18
p(2 left and 0 right) = .1^2 = .01
total probability is .81 + .18 + .01 = 1 as it should.
