SOLUTION: Dawn is a sefood chef and can stuff a large party of shrimp in 6 hours. If her brother helps her, they can stuff the large party pack of shrimp in 4 hours. If Dawn gets sick, how l

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Question 261279: Dawn is a sefood chef and can stuff a large party of shrimp in 6 hours. If her brother helps her, they can stuff the large party pack of shrimp in 4 hours. If Dawn gets sick, how long would it take her brother to stuff the large party of shrimp himself?
Found 3 solutions by richwmiller, solver91311, josmiceli:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
4/6+4/x=1
x=12
He can do it in 12 hours alone. In four hours the sister can do 2/3 of the job and he does 1/3 in four hours.












Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


If A can do a job in x time periods, then A can do of the job in 1 time period. Likewise, if B can do the same job in y time periods, then B can do of the job in 1 time period.

So, working together, they can do



of the job in 1 time period.

Therefore, they can do the whole job in:



time periods.

You are given that and that the combined time is 4, so:



Solve for

John


Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The key to this problem is:
(Dawn's rate of stuffing) + (Brother's rate of stuffing)
= (their rate stuffing together)
The rates are in units of (large party packs)/hour
Dawn's rate = 1%2F6
Let b = Brother's rate of stuffing
given:
1%2F6+%2B+b+=+1%2F4
b+=+1%2F4+-+1%2F6
Multiply both sides by 12
12b+=+3+-+2
b+=+1%2F12
The brother stuffs 1 party pack in 12 hrs working alone