SOLUTION: width of a rectangle is 6 and the diagonal is 10 what is the area?

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Question 261278: width of a rectangle is 6 and the diagonal is 10 what is the area?
Found 2 solutions by richwmiller, Stitch:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
You should recognize this as multiple of a 3,4,5 right triangle.
The other side is 8. So 8*6=48 =area

Answer by Stitch(470) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a rectangle is found by multiplying the length by the width. In your example, only the width was given so we need to find the length.
The Pythagorean theorem states that in any right triagle, A%5E2+%2B+B%5E2+=+C%5E2
Where C is the hypotenuse (or the diagonal)
A and B represent the sides of the triangle but it does not matter which one so We will set A = 6 (the given width)
and C = 10 (hypotenuse)
The equation: 6%5E2+%2B+B%5E2+=+10%5E2%29%0D%0ASimplify+the+equation%0D%0A%7B%7B%7B36+%2B+B%5E2+=+100
Subtract 36 from both sides
B%5E2+=+64
Take the square root of both sides
highlight%28B+=+8%29
The length of the retangle is 8
Now we can find the area of the rectangle:
A = L * W
Area = 8 * 6
Area = 48 square units